

Course 1, Unit 3  Linear Functions
Overview
In the Linear Functions unit, students learn how to recognize
situations in which key variables change at a constant rate. They learn
how to express and interpret those patterns of change in data tables,
straight line graphs, and rules in the form y = a + bx.
They identify and interpret the slopes and intercepts of linear graphs.
They learn techniques for solving linear equations and inequalities that
arise in science and business problems. They also learn to evaluate and
solve linear equations using graphs, tables, paperandpencil techniques.
Some of these topics are often introduced in middle school math courses.
Encourage your student to recall these ideas. Some of these questions may
be helpful.
Students will frequently use the language "rate of change" when talking
about the "slope" of a linear function. (See page 155.) Also
note that the letter "b" is not reserved almost exclusively for the yintercept
as you may have experienced in your mathematics program (with the form y = mx + b).
The y = a + bx form emphasizes the modeling
or statistical approach to linear functions where a is the starting
value or yintercept and b is the rate of change. (See
page 157.) One goal is to help students develop flexible use
of variables. Thus, you will notice many different letters representing
linear functions throughout the curriculum.
Further work toward developing proficiency with manipulating symbols
occurs in subsequent units and courses. Practice for the skills developed
in this unit is incorporated in the On Your Own Review tasks and the
Practicing for Standardized Test masters at the end of this and subsequent
units.
Key Ideas from Course 1, Unit 3

Linear data patterns: A relationship between variables x and y is
called linear if the graph of related (x, y) values is
a straight line. This graph pattern occurs when there is a constant
difference between successive y values as x values
change uniformly. That is, the ratio (change in y)/(change
in x) is constant. For example, in the next graph and accompanying
table, (5.5  1)/(5  2) = (13  7)/(10  6) = 1.5.

Linear function rules (equations): Every linear relationship
can be expressed with an algebraic rule in the form y = a + bx, where a indicates
the yintercept, (0, a) of the graph and b indicates
the slope of the graph and the rate of change in y values. (See
pages 157161.)

Modeling linear data patterns: Exact linear relationships
can be expressed with algebraic rules in the form y = a + bx.
But in many practical problems, experimental data might suggest,
but not exactly fit, a linear pattern. In such cases, it is often
useful to summarize the data trend by drawing a line that matches
the scatterplot of (x, y) data pairs and to find
the rule (formula) relating y and xcoordinates of
points on that line. For example, the following graph shows 7 data
points and the graph of a line that matches the pattern in those
data quite well. (See pages 161167.)
 Solving a linear equation: Students have graphic, numeric,
and symbolic strategies for finding the value of x that makes
equations like a + bx = c true.
For example, to solve the equation 5 + 4x = 13,
they can scan a table or graph of y = 5 + 4x in
search of points with coordinates (x, 13). They can also
apply properties of equality to reason like this:
If 5 + 4x = 13, then 4x = 8
(subtract 5 from both sides).
If 4x = 8, then x= 2 (divide both sides
by 4).

Solving systems of linear equations: In this unit, students
solve simple systems of linear equations like y = 3x and y = 5  2x. That
means finding a pair of values (x, y) that satisfy both
conditions. Once again, they have at least three strategies available
for this kind of problem. They can graph the two linear functions
and look for coordinates of the intersection point. They can scan
tables of values for the two functions, looking for points where
a single x value produces the same y value
for each.

X 
Y_{1} 
Y_{2} 
0 
0 
5 
0.5 
1.5 
4 
1 
3 
3 
1.5 
4.5 
2 
2 
6 
1 

They can also use symbolic reasoning as follows:
If y = 3x and y = 5  2x, then
3x = 5  2x.
So, 5x = 5 (add 2x to both sides).
So, x = 1 (divide both sides by 5).
So, y = 3 (substitute x = 1 in
either function rule).
